Embibe Experts Solutions for Chapter: Electrochemistry, Exercise 5: Exercise 5

Which of the following options will be correct for the stage of half completion of the reaction $\mathrm{A}\rightleftharpoons \mathrm{B}$?

How much will the reduction potential of a hydrogen electrode change when its solution initially at $\mathrm{pH}=0$ is neutralised to $\mathrm{pH}=7$ ?

Assume that partial pressure of hydrogen gas= 1 atm in the reaction.

If $x$ is the specific resistance $($in ${\mathrm{S}}^{-1}\mathrm{cm})$ of the electrolyte solution and $y$ is the molarity of the solution, then ${\mathrm{\Lambda }}_{\mathrm{m}}$ (in $\mathrm{S} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1}$) is given by

The standard EMF of a galvanic cell involving cell reaction with $\mathrm{n}=2$ is found to be $0.295\mathrm{V}$ at $25°\mathrm{C}$. The equilibrium constant of the reaction would be:(Given $\mathrm{F}=96500{\mathrm{Cmol}}^{-1}; \mathrm{R}=8.314{\mathrm{JK}}^{-1}{\mathrm{mol}}^{-1}$)

A smuggler could not carry gold by depositing iron on the gold surface since

The correct order of increasing oxidizing power is

The hydrogen electrode is dipped in a solution of $\mathrm{pH}=3$ at $25°\mathrm{C}$. The potential of the cell would be (value of $2.303\mathrm{RT}/\mathrm{F}$ is $0.059 \mathrm{V}$)

In electrolysis of $\mathrm{NaCl}$, when platinum electrode is taken, ${\mathrm{H}}_2$ is liberated at the cathode while with mercury cathode, it forms sodium amalgam. This is because: