Exercise 5

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Embibe Experts Chemistry Solutions for Exercise 5

Simple step-by-step solutions to Exercise 5 questions of Thermodynamics from Alpha Question Bank for Medical: Chemistry. Also get 3D topic explainers, cheat sheets, and unlimited doubts solving on EMBIBE.

Questions from Exercise 5 with Hints & Solutions

EASY
NEET
IMPORTANT

The heat of reaction for

C10H8s+12O2g10CO2g+4H2O(l) at constant volume is -1228.2 kcal at 250C. The heat of reaction at constant pressure and same temperature is

EASY
NEET
IMPORTANT

For the reaction, N2+3H22NH3, which one of the following is correct regarding ΔH?

MEDIUM
NEET
IMPORTANT

A gas expands adiabatically at a constant pressure, such that TV-1/2. The value of γCp,m/Cv,m of the gas will be:

HARD
NEET
IMPORTANT

S1: Molar heat at a constant pressure = Molar heat at a constant volume +PΔV
S2: ΔHsub =ΔHfusion +ΔHvap 
S3: Pressure is an intensive property.
S4: For reaction 2A(g)+B(g) (g)  ΔH=-x  kJ, then for reaction
32C(g)-A(g)+B2(g)  ΔH=X2kJ

MEDIUM
NEET
IMPORTANT

Stearic acid CH3CH216CO2H is a fatty acid, the part of fat that stores most of the energy. 1.0 g of stearic acid was burned in a bomb calorimeter. The bomb had a heat capacity of 652 J/C. If the temperature of 500 g water c=4.18 J/gC increase from 25.0 to 39.3°C, how much heat was released when the stearic acid was burned? [GivenCpH2O=4.18 J/8°C

MEDIUM
NEET
IMPORTANT

Use the following data to calculate the enthalpy of formation of As2O3:
(i) As2O3(s)+3H2O+aq2H3AsO3(aq) ΔH=+7550 cal
(ii) As(s)+32Cl2(g)AsCl3() ΔH=-71390 cal
(iii) AsCl3()+3H2O+aqH3AsO3(aq)+3HCl(aq);  ΔH=-17580cal
(iv) HCl(g)+aqHCl(aq) ΔH=-17315 cal
(v) 12H2(g)+12Cl2(g)HCl(g) ΔH=-22000 cal
(vi) H2(g)+12O2(g)H2O() ΔH=-68360 cal

MEDIUM
NEET
IMPORTANT

From the following data calculate the enthalpy change for the sublimation of ice at 223 K [mean heat capacity of ice =2 JK-1gm-1, mean heat capacity of H2O()=4.2 JK-1gm-1, mean heat capacity of H2O(v)=1.85 JK-1gm-1, enthalpy of fusion of ice at 0°C=334 Jgm-1, enthalpy of evaporation of water
at 100°=2255  J gm-1