Embibe Experts Solutions for Chapter: Alternating Current, Exercise 3: Exercise-3

The $RMS$ value of potential difference $V$ shown in the figure is:

Which of the following combinations should be selected for better tuning of an $LCR$ circuit used for communication

The potential differences across the resistance, capacitance and inductance are $80 \mathrm{V}\text{,} 40 \mathrm{V}$ and $100 \mathrm{V}$, respectively in an $\mathrm{LCR}$ circuit. The power factor of this circuit is,

An inductor $20 \mathrm{mH}$, a capacitor $100 \mathrm{\mu F}$ and a resistor $50 \mathrm{\Omega }$ are connected in series across a source of emf, $v=10\sin \left(314t\right)$. The power loss in the circuit is:

In a series $LCR$ circuit $R=200 \mathrm{\Omega }$ and the voltage and frequency of the main supply is $220 \mathrm{V}$ and $50 \mathrm{Hz}$ respectively. On taking out the capacitance from the circuit the current lags behind the voltage by $30°.$ On taking out the inductor from the circuit the current leads the voltage by $30°.$ The power dissipated in the $LCR$ circuit is

In an A.C. circuit, the instantaneous $\mathrm{e}.\mathrm{m}.\mathrm{f}.$ and current are given by $e=100\sin \left(30t\right) \mathrm{V}$, $I=20\sin \left(30t-\frac{\pi }{4}\right) \mathrm{A}$. In one cycle of A.C., the average power$\left(\text{in watt}\right)$ consumed by the circuit and the wattless current$\left(\text{in ampere}\right)$ are, respectively:
 

A power transmission line feeds input power at $2300 \mathrm{V}$ to a step down transformer with its primary windings having $4000$ turns. The output power is delivered at $230 \mathrm{V}$ by the transformer. If the current in the primary of the transformer is $5 \mathrm{A}$ and its efficiency is $90\%,$ the output current would be

In the above circuit $C=\frac{\sqrt{3}}{2} \mathrm{mF},R_2=20 \mathrm{\Omega } L=\frac{\sqrt{3}}{10}\mathrm{H}$ and $R_1=10 \mathrm{\Omega }$ Current in $L-R_1$ path is $I_1$ and in $C-R_2$ path it is $I_2$. The voltage of A.C. source is given by $V=200\sqrt{2}\sin \left(100t\right) \mathrm{Volts}$, the phase difference between $I_1$ and $I_2$ is :