Embibe Experts Solutions for Chapter: Circular Motion, Exercise 1: Exercise-1

A particle of mass $m$ is moving with constant velocity $\overrightarrow{v}$ on smooth horizontal surface. A constant force $\overrightarrow{F}$ starts acting on particle perpendicular to velocity $v$. Radius of curvature after force $F$ start acting is:

A car moving on a horizontal road may be thrown out of the road in taking a turn

If angular displacement of a particle moving on a curved path be given as, $\theta =1.5\mathrm{t}+2t^2,$ where $t$ is in sec, the angular velocity at $t=2\sec ,$ will be

A wheel starts rotating from rest with constant $\alpha$ and attains an angular velocity of $60 {\mathrm{rads}}^{-1}$ in $5 \mathrm{s}$. The total angular displacement in radians will be

A fan is running at $3000 \mathrm{rpm}.$ It is switched off. It comes to rest by uniformly decreasing its angular speed in $10 \mathrm{s}$. The total number of rotations in this period.

In the pulley system (stick to each other) shown, if radii of the bigger and smaller pulley are $2 \mathrm{m}$ and $1 \mathrm{m}$ respectively and the acceleration of block $A$ is $5 \mathrm{m} {\mathrm{s}}^{-2}$ in the downward direction, then the acceleration of block $B$ will be:

$P$ is the point of contact between a wheel and the ground. The radius of the wheel is $1 \mathrm{m}$. The wheel rolls on the ground without slipping. The displacement of point $P$, when the wheel completes half rotation is

A disc is moving without slipping on ground then the relation between magnitude of velocity of points $P$, $C$ and $Q$ is [distance $CP=CQ$]