Embibe Experts Solutions for Chapter: Chemical Kinetics, Exercise 1: EXERCISE-1

When the rate is determined by the change in concentration of two different reactants, then the kinetic equation may be expressed as

If a graph is plotted between $\log \left(\mathrm{a}-\mathrm{x}\right)$ and $\mathrm{t}$, the slope of the straight line is equal to $-0.03$. The specific reaction rate will be :

The rate law for the reaction : $2\mathrm{C}+\mathrm{D}\to \mathrm{A}+\mathrm{E}$ is $-\frac{\mathrm{d}\left[\mathrm{D}\right]}{\mathrm{dt}}=\mathrm{k}{\left[\mathrm{C}\right]}^2\left[\mathrm{D}\right]$

If $\mathrm{C}$ is present in large excess, the order of the reaction will be -

The dissociation of nitrogen pentoxide is a first order reaction. In first 24 minutes $75\%$ of nitrogen pentaoxide is dissociated. What amount of nitrogen pentaoxide will be left behind after one hour of start of the reaction?

The half life period of a chemical reaction is given by : ${\mathrm{t}}_1\propto \frac{1}{{\mathrm{a}}^{\mathrm{n}-1}}$

The order of the reaction is :

During study of a liquid phase reaction $\mathrm{A}\left(\mathrm{aq}\right)\to \mathrm{B}\left(\mathrm{aq}\right)+\mathrm{C}\left(\mathrm{aq}\right)$ the variation in concentration of $\mathrm{B}$ with time is given: 

The initial rate of reaction was?

For the reaction, $2 \mathrm{A}+\mathrm{B}\to$ Products, the following initial rates were obtained at various initial concentrations:

The rate law for the reaction is :

In the Wilhelmey equation of a first order reaction ${\mathrm{C}}_{\mathrm{t}}={\mathrm{C}}_0{\mathrm{e}}^{-\mathrm{kt}}$ if the initial concentration ${\mathrm{C}}_0$ is increased $\mathrm{m}$ times then