Embibe Experts Solutions for Chapter: Capacitance, Exercise 1: Exercise-1

In the figure shown the plates of a parallel plate capacitor have unequal charges. Its capacitance is '$C$'. $P$ is a point outside the capacitor and close to the plate of charge-$Q$. The distance between the plates is '$d$' then which statement is wrong

A parallel plate capacitor is made by stacking $n$ equally spaced plates connected alternately. If the capacitance between any two plates is $C,$then the resultant capacitance is

A parallel plate capacitor of capacitance $C$ (without dielectrics) is filled by dielectric slabs as shown in figure. Then the new capacitance of the capacitor is

Dielectric sheet placed between the plates of parallel plate capacitor. Now capacitor is charged and battery is disconnected. Now $t=0$ sheet is taken out very slowly then which of the following is correct for the variation of capacitance with time

A fully charged capacitor has a capacitance $C$. It is discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity $S$ and mass $m$. If the temperature of the block is raised by$\Delta T$, the potential difference $V$ across the capacitor is 

The capacitance $\left(C\right)$ for an isolated conducting sphere of radius $a$ is given by $4\pi {\epsilon }_{0}a$. This sphere is enclosed within an earthed concentric sphere. The ratio of the radii of the spheres being $\frac{n}{\left(n-1\right)}$ then the capacitance of such a sphere will be increased by a factor-

Four identical plates $1,2,3$ and $4$ are placed parallel to each other at equal distance as shown in the figure. Plates $1$ and $4$ are joined together and the space between $2$ and $3$ is filled with a dielectric of dielectric constant $k=2$. The capacitance of the system between $1$ and $3 \& 2$ and $4$ are $C_1$ and $C_2$ respectively. The ratio $\frac{C_1}{C_2}$ is-

In the circuit shows, all capacitors are identical., Initially, the switch is open and the capacitor marked $\left(C_1\right)$ is the only one charged. After the switch is closed and the equilibrium is reestablished, the charge on the capacitor marked $\left(C_1\right)$ is $Q$. What was the initial charge $Q_0$ on that capacitor?