Embibe Experts Solutions for Chapter: Electromagnetic Induction, Exercise 2: Exercise-2

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Embibe Experts Physics Solutions for Exercise - Embibe Experts Solutions for Chapter: Electromagnetic Induction, Exercise 2: Exercise-2

Attempt the free practice questions on Chapter 27: Electromagnetic Induction, Exercise 2: Exercise-2 with hints and solutions to strengthen your understanding. Beta Question Bank for Engineering: Physics solutions are prepared by Experienced Embibe Experts.

Questions from Embibe Experts Solutions for Chapter: Electromagnetic Induction, Exercise 2: Exercise-2 with Hints & Solutions

HARD
JEE Main/Advance
IMPORTANT

PQ is an infinite current carrying conductor. AB and CD are smooth conducting rods on which a conductor EF moves with constant velocity V as shown. The force needed to maintain constant speed of EF is

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HARD
JEE Main/Advance
IMPORTANT

Two different coils have self-inductances L1=8mH and L2=2mH. The current in one coil is increased at a constant rate. The current in the second coil is also increased at the same constant rate. At a certain instant of time, the power given to the two coils is the same. At that time, the current, the induced voltage and the energy stored in the first coil are i1, V1 and W1 respectively. Corresponding values for the second coil at the same instant are i2, V2 and W2 respectively. Then:

MEDIUM
JEE Main/Advance
IMPORTANT

An electron is moving in a circular orbit of radiusR with an angular acceleration α. At the centre of the orbit is kept a conducting loop of radius r,(r<<R). The e.m.f. induced in the smaller loop due to the motion of the electron is

HARD
JEE Main/Advance
IMPORTANT

A long straight wire is parallel to one edge as in figure. If the current in the long wire is varies in time as I=I0e-tτ, what will be the induced emf in the loop?

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HARD
JEE Main/Advance
IMPORTANT

The figure shows an isosceles triangle wire frame with apex angle equal to π2. The frame starts entering into the region of uniform magnetic field B with constant velocity v at t=0. The longest side of the frame is perpendicular to the direction of velocity. If i is the instantaneous current through the frame then choose the alternative showing the correct variation of i with time.

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MEDIUM
JEE Main/Advance
IMPORTANT

The frequency of oscillation of current in the inductor is

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MEDIUM
JEE Main/Advance
IMPORTANT

At a moment t=0 when charge on capacitor C1 is zero, the switch is closed. If I0 be the current through inductor at that instant, for t>0,

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HARD
JEE Main/Advance
IMPORTANT

In the circuit shown in the figure, R=LC. Switch S is closed at time t=0. The current through C and L would be equal after a time t equal to

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