Embibe Experts Solutions for Chapter: Classification of Elements and Periodicity in Properties, Exercise 3: EXERCISE-II (Previous Year Questions)

The atomic number $\mathrm{Ag}$ is $47$. in the same group the atomic number of elements placed above and below $\mathrm{Ag}$ will be:

In the general electronic configuration - $(\mathrm{n}-2){\mathrm{f}}^{1-14}(\mathrm{n}-1){\mathrm{d}}^{0-1}{\mathrm{ns}}^2$if value of $\mathrm{n}=7$ the configuration will be of -

On the basis of the given part of the periodic table, an incorrect statement is

If total $110$ elements are present in the periodic table then how many of them contain ${\mathrm{e}}^{-}$ in $\mathrm{f}$ the subshell:

The internuclear distance in ${\mathrm{H}}_2$ and ${\mathrm{Cl}}_2$ molecules are $74$ and $198 \mathrm{\AA }$, respectively. The bond length of $\mathrm{HCl}$ maybe. $\left(\mathrm{EN} \text{of} \mathrm{H}=2.1 \mathrm{Cl}=3.0\right)$

These are $3$ elements $\mathrm{A}, \mathrm{B}$ and $\mathrm{C}$. Their atomic number are ${\mathrm{Z}}_1, {\mathrm{Z}}_2, {\mathrm{Z}}_3$, respectively. If ${\mathrm{Z}}_3-{\mathrm{Z}}_1=2$ and $\frac{Z_1+Z_3}{2}=Z_2$ and the electronic configuration of an element $\mathrm{C}$ is  $\left[\mathrm{Ar}\right]3{\mathrm{d}}^{2}4{\mathrm{s}}^2$ the correct order of atomic radius is:

$\mathrm{K}\stackrel{\mathrm{a}}{⟶}{\mathrm{K}}^{+}\stackrel{\mathrm{b}}{⟶}{\mathrm{K}}^{+2}$

$\mathrm{Ca}\stackrel{\mathrm{c}}{\to }{\mathrm{Ca}}^{+}\stackrel{\mathrm{d}}{\to }{\mathrm{Ca}}^{+2}$

If $\mathrm{a}, \mathrm{b}, \mathrm{c}, \mathrm{d}$ are ionisation energies, the which of the following order is not correct -

If electron affinity of an element $\mathrm{M}$ is $\mathrm{xkJ}/\mathrm{mol}$ than ionisation potential of this element: