In the given circuit R = 100 Ω . If voltage leads current by 60 ∘ then find current supply by source.

The voltage applied is V = 200 sin 100 π t V Voltage leads current by π 3 , therefore the current I = I 0 sin 100 π t - π 3 A , The phase difference between current and voltage is π 3 and current is lagging . From the Phasor diagram, the phase angle tan ϕ = X L - X C R ⇒ tan π 3 = X L - X C R ⇒ X L - X C = 3 × 100 The impedance Z = R 2 + ( X L - X C ) 2 Z = ( 100 ) 2 + ( 100 3 ) 2 ⇒ Z = 200 Ω , The impedance Z = V 0 I 0 ⇒ I 0 = 200 200 ⇒ I 0 = 1 A Therefore, the current I RMS = I 0 2 = 1 2 ⇒ I RMS = 1 2 A

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Beta Question Bank for Medical: Physics>Chapter 28 - Alternating Current>BEGINNER'S BOX - 5

Embibe Experts Solutions for Chapter: Alternating Current, Exercise 5: BEGINNER'S BOX - 5

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Embibe Experts Physics Solutions for Exercise - Embibe Experts Solutions for Chapter: Alternating Current, Exercise 5: BEGINNER'S BOX - 5

Attempt the practice questions on Chapter 28: Alternating Current, Exercise 5: BEGINNER'S BOX - 5 with hints and solutions to strengthen your understanding. Beta Question Bank for Medical: Physics solutions are prepared by Experienced Embibe Experts.