Embibe Experts Solutions for Chapter: Alternating Current, Exercise 8: Exercise (Analytical Questions)

A coil has resistance of $10 \mathrm{\Omega }$ and an inductance of $0.4 \mathrm{H}$. It is connected to an AC source of $6.5 \mathrm{V}\text{,} \frac{30}{\mathrm{\pi }} \mathrm{Hz}$. The average power consumed in the circuit is,

In series RLC a.c. circuit, L = 1 H, C = 1 µF and R = 20$\Omega$ is connected across a supply voltage of 10 volt. At resonance, voltage across L is :- 

In series RLC circuit, L = 1 mH, C = 0.1 µF, R = 10$\Omega$ and applied voltage is V = 9 sin$\omega$t. At resonance peak voltage across capacitor is :  

When $100 \mathrm{V}$ d.c. is applied across a solenoid a current of $1.0 \mathrm{A}$. flows in it. When $100 \mathrm{V}$ a.c. is applied across the same coil, the current drops to $0.5 \mathrm{A}$. If the frequency of the a.c. source is $50 \mathrm{Hz}$ the impedance and inductance of the solenoid are :- 

An alternating emf of angular frequency $\omega$ is applied across an inductance. The instantaneous power developed in the circuit has an angular frequency:-

The inductance of the oscillatory circuit of a radio station is 10 milli henry and its capacitance is 0.25µF. Taking the effect of the resistance negligible, wavelength of the broadcasted waves will be (velocity of light = 3.0 × 10⁸ m/s, $\pi$ = 3.14) : 

A coil has an inductance of$0.7 \mathrm{H}$ and is joined in series with a resistance of $220 \mathrm{\Omega }$. When the alternating emf of $220 \mathrm{V}$ at $50 \mathrm{Hz}$ is applied to it then the phase through which current lags behind the applied emf and the wattles component of current in the circuit will be respectively : 

When 100V D.C. is applied across a coil a current of 1A flows through it. When 100V A.C. of 50 Hz is applied to the same coil only 0.5A flows. The inductance of the coil is :-