Embibe Experts Solutions for Chapter: Capacitance, Exercise 11: BEGINNER'S BOX - 11

In the circuit diagram shown, all the capacitors are in $\mu F$. The equivalent capacitance between points $A$ and $B$ is  (in $\mu F$)

Two capacitances $C_1$ and $C_2$ are connected in series; assume that $C_1<C_2$. The equivalent capacitance of this arrangement is $C,$ where :

In the following circuit, the resultant capacitance between $\mathrm{A}$ and $\mathrm{B}$ is $1\mu \mathrm{F}$. Then value of $\mathrm{C}$ is

A capacitor of capacitance $5 \mathrm{\mu }F$ is connected, as shown in the figure. The internal resistance of the cell is $0.5 \mathrm{\Omega }$. The amount of charge on the capacitor plate will be

In the given circuit, the potential difference across 3 µF capacitor will be : 

If the potential of $A$ is $10 \mathrm{V},$ then potential of $B$ is: