Embibe Experts Solutions for Chapter: Capacitance, Exercise 13: Exercise (Conceptual Questions)

Two spherical conductors $A$ and $B$ of radius $a$ and $b\left(\mathit{b}\mathit{>}\mathit{a}\right)$ are placed in air concentrically $B$ is given charge $+Q$ coulomb and $A$ is grounded. The equivalent capacitance of these is :-

A capacitor of capacitance $C_1$ is charged upto potential $V$ and then connected in parallel to an uncharged capacitor of capacitance $C_2$. The final potential difference across each capacitor will be

A $40 \mathrm{F}$ capacitor in a defibrillator is charged to, $3000 \mathrm{V}$. The energy stored in the capacitor is sent through the patient during a pulse of duration, $2 \mathrm{ms}$. The power delivered to the patient is

Two metallic spheres of radii $R_1$ and $R_2$ are connected by a thin wire. If $+q_1$ and $+q_2$ are the charges on the two spheres then :

A parallel plate air capacitor is charged to a potential difference of $V$ volts. After disconnecting the charging battery, the distance between the plates of the capacitor is increased using an insulating handle. As a result, the potential difference between the plates, 

The energy required to charge a parallel plate condenser of plate separation $d$ and plate area of cross-section $A$ such that the uniform electric field between the plates is $E$, is 

Three capacitors, each of capacitance $C$ and of breakdown voltage $V$ are joined in series. The capacitance and breakdown voltage of the combination will be 

The energy density associated with the electric field will be -