Embibe Experts Solutions for Chapter: Electromagnetic Induction, Exercise 5: BEGINNER'S BOX - 5

A coil of $10 \mathrm{H}$ inductance and $5 \mathrm{\Omega }$ resistance is connected to $5 \mathrm{V}$ battery in series. The current in ampere in circuit $2 \mathrm{s}$ after switch is put on is,

An $L-R$ circuit consists of an inductance of $8 \mathrm{mH}$ and a resistance of $4 \mathrm{\Omega }$. The time constant of the circuit is,

In an $L-R$ circuit, time constant is that time in which current grows from zero to the value... (where, $I_0$ is steady-state current).

An inductor of $20 \mathrm{H}$ and a resistance of $10 \mathrm{\Omega }$ are connected to a battery of $5 \mathrm{V}$ in series. Then, the initial rate of change of current is,

A coil of $L=5\times {10}^{-3} \mathrm{H}$ and $R=18 \mathrm{\Omega }$ is abruptly supplied a potential of $5 \mathrm{V}$. What will be the rate of change of current in $0.001 \mathrm{s}$ $\left(e^{-3.6}=0.0273\right)$?

A coil of inductance $8.4 \mathrm{mH}$ and resistance $6 \mathrm{\Omega }$ is connected to a $12 \mathrm{V}$ battery in series. The current in the coil is $1 \mathrm{A}$ at approximately the time,

The dimensions of combination $\frac{L}{CVR }$ are same as dimensions of :-