Embibe Experts Solutions for Chapter: Electrostatics, Exercise 10: Exercise (Conceptual Questions)

A particle in a certain conservative electric field has potential energy given by $U=\frac{20xy}{z}.$ The force exerted on it is:

Consider a neutral conducting sphere. A positive point charge is placed outside the sphere. The net charge on the sphere is then

Two equal and like charges when placed $5 \mathrm{cm}$ apart experience a repulsive force of $0.144$ $\mathrm{N}$. The magnitude of the charge in micro coloumb will be:

Gauss law is given by ${\in }_0\oint \overrightarrow{E}.\overrightarrow{ds}=q,$ if net charge enclosed by Gaussian surface is zero then-.

If the electric field at a distance $x$ from the origin is given as $E=\frac{100}{x^2}$, then the potential difference between the points situated at $x=10 \mathrm{m}$ and $x=20 \mathrm{m}$ is,

The electric potential $V$ is given as a function of distance $x$ (metre) by $V=\left(5x^2+10x-9\right)$ volt. The value of electric field at $x=1$ is

Two charged spheres having radii $a$ and $b$ are joined with a wire then the ratio of electric field $E_a/E_b$ on their surface is -

Two charged parallel capacitors, each with separation between plates equal to $d$, are separated by a large distance $L>>d$. Then the force of interaction between them is proportional to: