Embibe Experts Solutions for Chapter: Kinematics, Exercise 14: Exercise (Analytical Questions)

A projectile is fired at an angle of $45°$ with the horizontal. The elevation angle of the projectile at its highest point as seen from the point of projection is:

The motion of a particle along a straight line is described by the equation $x=8+12t–t^3$, where $x$ is in $\mathrm{metres}$ and $t$ in $\mathrm{seconds}$. The retardation of the particle when its velocity becomes zero is:

The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is:

A particle has initial velocity $\left(2\hat{\mathrm{i}}+3\hat{\mathrm{j}}\right)$ and acceleration $\left(0.3\hat{\mathrm{i}}+0.2\hat{\mathrm{j}}\right)$. The magnitude of velocity after $10 \mathrm{seconds}$ will be

A stone is dropped from a height $h$. It hits the ground with a certain momentum $P$. If the same stone is dropped from a height $100 \%$ more than the previous height, the momentum when it hits the ground will change by

A stone falls freely under gravity. It covers distances $h_1$, $h_2$ and $h_3$ in the first $5 \mathrm{seconds}$, the next $5 \mathrm{seconds}$ and the next $5 \mathrm{seconds}$, respectively. The relation between $h_1$, $h_2$ and $h_3$ is:

The velocity of a projectile at the initial point $A$ is $\left(2\hat{\mathrm{i}}+3\hat{\mathrm{j}}\right) \mathrm{m} {\mathrm{s}}^{-1}$. Its velocity (in $\mathrm{m} {\mathrm{s}}^{-1}$) at a point $B$ is:

A projectile is projected from the ground with initial velocity $\overrightarrow{u}=u_0\hat{i}+v_0\hat{j}$. If the acceleration due to gravity $\left(g\right)$ is along negative $y-$direction, then find the maximum displacement in $x-$direction.