A rectangular film of liquid is 5 cm long and 3 cm wide. If the work done in increasing its area to 9 cm × 5 cm is 6 x 10 - 4 Joule . Find the surface tension of the liquid ?

Given, initial area A 1 = 5 × 3 cm 2 = 15 cm 2 Final area A 2 = 9 × 5 cm 2 = 45 cm 2 Change in area, ∆ A = 45 - 15 = 30 cm 2 Work done, W = 6 × 10 - 4 Joule We know, work done = surface tension × change in area ⇒ W = 2 T ∆ A ⇒ T = W 2 ∆ A = 6 × 10 - 4 2 × 30 × 10 - 4 ⇒ T = 0 . 1 Nm - 1

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Beta Question Bank for Medical: Physics>Chapter 14 - Viscosity and Surface Tension>BEGINNER'S BOX - 2

Embibe Experts Solutions for Chapter: Viscosity and Surface Tension, Exercise 2: BEGINNER'S BOX - 2

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Beta Question Bank for Medical: Physics>Chapter 14 - Viscosity and Surface Tension>BEGINNER'S BOX - 2>Q 7

A rectangular film of liquid is $5 cm$ long and $3 cm$ wide. If the work done in increasing its area to $9 cm \times 5 cm is 6 x 10^{- 4} Joule$ . Find the surface tension of the liquid ?