Embibe Experts Solutions for Chapter: Wave Optics, Exercise 8: Exercise (Analytical Questions)

In an interference pattern of two waves, the fringe width is $\beta$. If the frequency of source is doubled, then fringe width becomes,

The intensity of the central fringe obtained in the interference pattern due to two identical slit sources is $I$. When one of the slits is closed, then the intensity at the same point is $I_0$. Then, the correct relation between $I$ and $I_0$ is,

In double slit experiment, the angular width of the fringes is 0.20° for the sodium light ($\lambda =5890 \stackrel{o}{A}$). In order to increase the angular width of the fringes by 10%, the necessary change in the wavelength is :

The direction of the first secondary maximum in the Fraunhofer diffraction pattern at a single slit is given by ($a$ is the width of the slit),

A light has amplitude $A$ and the angle between analyser and polariser is $60°$. Light transmitted by analyser has amplitude,

In the Young's double slit experiment, the central maxima is observed to be $I_0$. If one of the two slits is covered, then the intensity at the central maxima will become

If diffraction occurs through a single slit, then intensity of first secondary maxima become ___$\%$ of central maxima.

The intensity of light pulse travelling in an optical fibre decrease according to the relation

$I=I_0{e}^{-\alpha x}$
The intensity of light is reduced to 20% of its initial value after a distance x equal to