Embibe Experts Solutions for Chapter: Chemical Kinetics, Exercise 2: Level 2

The accompanying figure depicts the change in concentration of species $\mathrm{X}$ and $\mathrm{Y}$ for the elementary reaction $\mathrm{X}\to \mathrm{Y}$ as a function of time. The point of intersection of two curves represents:

Consider the reaction $2\mathrm{A}+\mathrm{B}\to$ product. When concentration of $\mathrm{B}$ alone was doubled the half-life did not change. When concentration of $\mathrm{A}$ alone was doubled the rate increased by two times. The unit of rate constant for this reaction is:

If $\frac{\mathrm{d}\left[{\mathrm{NH}}_3\right]}{\mathrm{dt}}=34 \mathrm{M}/\mathrm{hr}$ for the reaction ${\mathrm{N}}_2+3{\mathrm{H}}_2\rightleftharpoons 2{\mathrm{NH}}_3,$ then $\frac{-\mathrm{d}\left[{\mathrm{H}}_2\right]}{\mathrm{dt}}$ in $\mathrm{M}/\mathrm{hr}$ will be:

$\mathrm{xA}\to \mathrm{yB},$ for a given hypothetical reaction. If rate expression is $\log \left[-\frac{\mathrm{d}\left[\mathrm{A}\right]}{\mathrm{dt}}\right]=\log \left[\frac{\mathrm{d}\left[\mathrm{B}\right]}{\mathrm{dt}}\right]+0.477,$ then the ratio of $\mathrm{x}$ and $\mathrm{y}$ will be:

What will be the order of reaction for a chemical change having the graph between $\log {\mathrm{t}}_{1/2}$ vs $\log \mathrm{a}$ as shown below? $($where, $\mathrm{a}=$initial concentration of reactant; $\left.{\mathrm{t}}_{1/2}=\mathrm{half}-\mathrm{life}\right)$

For an elementary reaction $2\mathrm{A}+\mathrm{B}⟶{\mathrm{A}}_2\mathrm{B}$, if the volume of vessel is quickly reduced to half of its original volume, then what will happen to the rate of reaction?

For the zero-order reaction $\mathrm{A}\to \mathrm{B}+\mathrm{C};$ the initial concentration of $\mathrm{A}$ is $0.1 \mathrm{M}$. If the concentration of $\mathrm{A}=0.08 \mathrm{M}$ after $10$ minutes, then, its half-life and completion time are respectively

For an ideal gaseous reaction, the rate is expressed in terms of $\frac{\mathrm{dP}}{\mathrm{dt}}$ instead of $\frac{\mathrm{dC}}{\mathrm{dt}}$ (where $\mathrm{C}=\frac{\mathrm{n}}{\mathrm{V}}$ is concentration and $\mathrm{n}$ is the number of moles). What is the relation among these expressions, if $\mathrm{T}$ and $\mathrm{V}$ are constant?