Let f be the function defined by f x = x 2 - 1 x 2 - 2 x - 1 - 1 , x ≠ 1 1 2 , x = 1 .

The function is not continuous at x = 1

The function is continuous for all values of x

The function is continuous only for x > 1

The function is continuous at x = 1

f x = x sin 1 x , x ≠ 0 0 , x = 0 at x = 0 is

continuous but not differentiable

continuous as well as differentiable

differentiable but not continuous

neither continuous nor differentiable

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 17 - Continuity and Differentiability>VITEEE 2019 Shift 1

Embibe Experts Solutions for Chapter: Continuity and Differentiability, Exercise 1: VITEEE 2019 Shift 1

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Embibe Experts Mathematics Solutions for Exercise - Embibe Experts Solutions for Chapter: Continuity and Differentiability, Exercise 1: VITEEE 2019 Shift 1

Attempt the practice questions on Chapter 17: Continuity and Differentiability, Exercise 1: VITEEE 2019 Shift 1 with hints and solutions to strengthen your understanding. EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS solutions are prepared by Experienced Embibe Experts.

Questions from Embibe Experts Solutions for Chapter: Continuity and Differentiability, Exercise 1: VITEEE 2019 Shift 1 with Hints & Solutions

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 17 - Continuity and Differentiability>VITEEE 2019 Shift 1>Q 1

Let $f$ be the function defined by $f (x) = \{\begin{cases} \frac{x^{2} - 1}{x^{2} - 2 |x - 1| - 1}, & x \neq 1 \\ \frac{1}{2}, & x = 1 \end{cases}$ .