Find the median of the following frequency distribution table: Variable x 4 6 8 10 12 14 16 Frequency f 2 4 5 3 2 1 4

Given table Variable x Frequency f Cumulative Frequency 4 2 2 6 4 6 8 5 11 10 3 14 12 2 16 14 1 17 16 4 21 ∑ f = 21 Here, N = ∑ f = 21 (odd number) Median = value of the N + 1 2 th term = 21 + 1 2 th term = 11 th term = 8 (From table) Hence, median is 8 .

The following table shows the ages of the patients admitted in a hospital during a year : Age (in years) 5 - 15 15 - 25 25 - 35 35 - 45 45 - 55 55 - 65 Number of patients 6 11 21 23 14 5 Find the mode of the data given above.

We have, Age (in years) 5 - 15 15 - 25 25 - 35 35 - 45 45 - 55 55 - 65 Number of patients 6 11 21 23 14 5 We observe that the class 35 - 45 has the maximum frequency. So, it is the modal class such that l = 35 , h = 10 , f = 23 , f 1 = 21 , f 2 = 14 Therefore, Mode = l + f - f 1 2 f - f 1 - f 2 × h = 35 + 23 - 21 2 23 - 21 - 14 × 10 = 35 + 20 11 = 35 + 1 . 82 = 36 . 82 Hence, the mode of the data is 36 . 82

Let log a m n = x ⇒ m n = a x ⇒ a x = m n . . . . . i Let log a m = b , log a n = c ⇒ m = a b , n = a c m n = a b a c = a b - c From equation i , ⇒ a x = a b - c ⇒ x = b - c ⇒ log a m n = log a m - log a n Hence, log m n = log m - log n .

E M B I B E

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 14 - Statistics>Madhya Pradesh Board-2018

Embibe Experts Solutions for Chapter: Statistics, Exercise 1: Madhya Pradesh Board-2018

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Embibe Experts Mathematics Solutions for Exercise - Embibe Experts Solutions for Chapter: Statistics, Exercise 1: Madhya Pradesh Board-2018

Attempt the free practice questions on Chapter 14: Statistics, Exercise 1: Madhya Pradesh Board-2018 with hints and solutions to strengthen your understanding. EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS solutions are prepared by Experienced Embibe Experts.