Embibe Experts Solutions for Chapter: Electrons and Photons, Exercise 1: MHT-CET 2017

Threshold frequency for a metal is $15\times {10}^{14} \mathrm{Hz}$. The light of wavelength $6000 Å$ falls on the metal surface. Which one of the following statements is correct? [velocity of light, $c=3\times {10}^8 \mathrm{m} {\mathrm{s}}^{-1}$]

The maximum velocity of the photoelectron emitted by the metal surface is $v$. Charge and mass of the photoelectron is denoted by $e$ and $m$ respectively. The stopping potential in volt is

If intensity of incident radiation in a photocell is increased, the stopping potential

A metal surface is illuminated by light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one fourth of its original value then the maximum KE of the emitted photoelectrons would be

Following graphs show the variation of stopping potential corresponding to the frequency of incident radiation $\left(\mathrm{f}\right)$ for a given metal. The correct variation is shown in graph ( ${\mathrm{f}}_0=$ Threshold frequency)

On a photosensitive material, when the frequency of incident radiation is increased by $30\%$, the kinetic energy of emitted photoelectrons increases from $0.4 \mathrm{eV}$ to $0.9 \mathrm{eV}$. The work function of the surface is