Embibe Experts Solutions for Chapter: Gravitation, Exercise 1: MHT-CET 2017

The depth $d$ at which the value of acceleration due to gravity becomes $\frac{1}{n}$ times the value at the earth's surface is $(R$= radius of the earth $)$

A body is projected vertically upwards from earth's surface with velocity $2v_e,$ where $v_{\mathit{e}}$ is escape velocity from earth's surface. The velocity when body escapes the gravitational pull is

Earth revolves round the sun in a circular orbit of radius $R$. The angular momentum of the revolving earth is directly proportional to

Binding energy of a revolving satellite at height $h$ is $3.5\times {10}^8 \mathrm{J}$. Its potential energy is

Two satellites $A$ and $B$ are revolving with critical velocities $v_{\mathit{A}}$ and $v_B$ around the earth, in circular orbits of radii $R$ and $2R$ respectively. The ratio $\frac{v_A}{v_B}$ is

What is the minimum energy required to launch a satellite of mass $m$ from the surface of the earth of mass $M$ and radius $R$ at an altitude $2R$?

A body is thrown from the surface of the earth with velocity $u \mathrm{m} {\mathrm{s}}^{-1}$. The maximum height in meter above the surface of the earth up to which it will reach is ($R=$radius of the earth, $g=$ acceleration due to gravity)

The ratio of the binding energy of a satellite at rest on earth's surface to the binding energy of a satellite of same mass revolving around the earth at a height $h$ above the earth's surface is $(R$= radius of the earth$)$.