Embibe Experts Solutions for Chapter: Kinematics, Exercise 1: TS EAMCET - 5 August 2021 Shift 1

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Embibe Experts Physics Solutions for Exercise - Embibe Experts Solutions for Chapter: Kinematics, Exercise 1: TS EAMCET - 5 August 2021 Shift 1

Attempt the free practice questions on Chapter 3: Kinematics, Exercise 1: TS EAMCET - 5 August 2021 Shift 1 with hints and solutions to strengthen your understanding. EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS solutions are prepared by Experienced Embibe Experts.

Questions from Embibe Experts Solutions for Chapter: Kinematics, Exercise 1: TS EAMCET - 5 August 2021 Shift 1 with Hints & Solutions

EASY
TS EAMCET
IMPORTANT

A stone falls freely under gravity. It covers distance, d1 and, d2 in the first 4 seconds, and the next, 8 seconds respectively. The ratio d2d1 is

EASY
TS EAMCET
IMPORTANT

The velocity of a particle moving along the x- axis varies as a function of time t as vt=1-3t2+2t3 m s-1 If its position at t=0 is x=0 then at =2 s, it's position is

MEDIUM
TS EAMCET
IMPORTANT

Two cars A and B initially at rest are moving in the same direction with accelerations, a1 and a2 respectively. After a certain time, they achieve velocities v1 and v2 respectively and are separated by a distance of 50 m. If a1-a2=4 m s-2, then the quantity v1-v2 will be

HARD
TS EAMCET
IMPORTANT

A rocket lifts off from the ground and accelerates upwards at 1 m s-220 seconds after liftoff a piece breaks off from the bottom of the rocket. After breaking off, how much time it takes approximately to reach the ground? (Take g=10 m s-2)

MEDIUM
TS EAMCET
IMPORTANT

The y-component of vector A is +3.0 m. If A makes an angle of 30° counter-clockwise from the positive y- axis, the magnitude of A is (assume A is in x-y plane)

MEDIUM
TS EAMCET
IMPORTANT

Two bodies were thrown simultaneously from the origin: one straight up and the other, at an angle, 60° to the vertical. The initial velocity of each body is equal to 10 m s-1 Neglecting the air resistance, the distance between the two bodies after t=2 s is ( Use g=10 m s-2)

EASY
TS EAMCET
IMPORTANT

A particle leaves the origin with initial velocity v=3i^ m s-1 and a constant acceleration a=-1i^-0.5j^m s-2. The position vector of particle, when it reaches its maximum x-coordinate, is

EASY
TS EAMCET
IMPORTANT

A particle is moving in xy-plane crosses the origin at time t=0. The equation of motion of the particle is y=4x2. If the velocity of the particle is v=(2i^+2j^) m s-1 and acceleration is a=(aj^) m s-2, then the magnitude of a is