Embibe Experts Solutions for Chapter: Magnetic Effect of Current, Exercise 1: Assam CEE 2017

A beam of protons with velocity $600 \mathrm{km} {\mathrm{s}}^{-1}$ enters a uniform magnetic field of $0.2 \mathrm{T}$. The velocity makes an angle of $30°$ with the magnetic field. The radius of the helical path will be

An electron moving with velocity $\overrightarrow{\mathrm{v}}=\hat{\mathrm{i}}{v}_{\mathrm{x}}$ enters a uniform magnetic field $\overrightarrow{\mathrm{B}}=\hat{\mathrm{k}}{B}_{\mathrm{z}}$. The electron experiences

A wire of radius $R$ carries a current $1$. The magnetic induction inside the wire, at a distance $r\left(<R\right)$, is

A uniform magnetic field of magnitude $1000 \mathrm{G}$ is directed vertically upward along $+z$ direction. A proton with kinetic energy $10 \mathrm{MeV}$ enters the chamber, moving horizontally along $+y$ direction. The magnitude of acceleration produced by the magnetic force acting on the proton as it enters the chambers is

A charged particle of mass $m$ and charge $q$ with energy $E$ enters a uniform transverse magnetic field $B$ and describes a circular path. The magnitude of the angular momentum of the particle along the circular path is $L$. If the particle had energy $2E$, the angular momentum would have been-

A particle of mass $M$ and charge $q$ is moving in a circle of radius $R$ with speed $v$, where $v\ll$ speed of light. The ratio of the magnetic moment of the particle to its angular momentum is

Two infinitely long parallel wires carry the same current in opposite directions. If both these currents are doubled and the separation between the wires is also doubled, the force per unit length on each wire

The magnetic field at the centre of a circular loop of area $A$ is $B$. The magnetic moment of the loop will be,