Embibe Experts Solutions for Chapter: Magnetic Effects of Current and Magnetism, Exercise 1: TS EAMCET - 10 August 2021 Shift 1

Electron moves to a region of uniform magnetic field $B$ in the plane perpendicular to $B.$ It finishes an orbit in  $1 \mu \mathrm{s}.$ What is the nearest value of $B$ among the following $[$ mass of electron $\left.=9\times {10}^{-31} \mathrm{kg}\right]$

A particle of charge, $q$ and mass, $m$ moves is a uniform magnetic field, $B$ with a speed, $V$. The average acceleration for $90°$ turn as it moves from point $1$ to $2$ as shown in the figure is $\alpha \left(\frac{qVB}{m}\right)$. The value of $\alpha$ is

A square loop of sides $2 \mathrm{m}$ lies in $X-Y$ plane and carries a current, $3\mathrm{A}$ and, is in the magnetic field coming out of the page (along $+Z$-axis). The field grows in strength at a rate, $2m \mathrm{T} {\mathrm{m}}^{-1}$ in the horizontal direction ($X$-axis). What is the force acting on it?

A square loop is made from a uniform wire as shown in the figure. If a battery is connected between the points $A \& C,$ then the magnitude of the magnetic field at the center of the square is

The magnitude of the magnetic field inside a solenoid of length, $300 \mathrm{cm}$ and made up of $450$ turns is $9\times {10}^{-3} \mathrm{T}$. The current carried by the solenoid is (assume the radius of solenoid << $300 \mathrm{cm}$ )

The strength of earth's magnetic field on the earth's surface is of the order: of

The dip angle at point, $P$ on earth's surface, is $45°$. If the dip angle is changed by $1\%$ then the change in the horizontal component of earth's magnetic field is:

In the magnetic meridian of a certain place, the horizontal component of the dip angle is $45°.$ What is the magnetic field of the earth at this location?
(Use Horizontal component of the magnetic field to be $0.26 \mathrm{G}$)