Embibe Experts Solutions for Chapter: Rotational Motion, Exercise 1: BITSAT 2017

A semicircular disc of mass $M$ and radius $R$ is free to rotate about its diameter. The moment of inertia of semicircular disc about a line perpendicular to its plane through centre is

A uniform solid cylindrical roller of mass $m$ is being pulled on horizontal surface with force $F$ parallel to the surface applied at its centre. If the acceleration of the cylinder is $a$ and it is rolling without slipping, then the value of $F$ is

A cylinder of mass $2 \mathrm{kg}$ is released from rest from the top of an inclined plane of inclination $30°$ and length $1 \mathrm{m}$. If the cylinder rolls without slipping, then its speed when it reaches the bottom is [$g=10 \mathrm{m} {\mathrm{s}}^{-2}$]

If the time period is doubled, then the angular momentum of the body will (provided the moment of inertia of the body is constant)

A uniform rod of length $l$ and mass $m$ is free to rotate in a vertical plane about $A$. The rod initially in horizontal position is released. The initial angular acceleration of the rod is (Moment of inertia of rod about $A$ is $\frac{m{l}^2}{3}$)