Here, the object is placed beyond from the convex lens. That means the distance of the object is more than twice the focal length of the lens. In the ray diagram, when a ray of light parallel to the principal axis of the lens from A falls on the lens along AD, it gets refracted by passing through second principal focus . Now, when another ray of light from A falls on the lens along AO through optical centre, it goes straight after refraction. The two refracted rays meet at A’. So A’ is the real image of A as it can be captured on a screen. If we draw perpendicular from A’ on principal axis we get A’B’ as the real image of the object AB. Thus, we can say that when an object is placed beyond , its image will be inverted, diminished and formed between and .
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Embibe Experts Solutions for Chapter: Light - Reflection and Refraction, Exercise 1: Karnataka Board-2019
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Embibe Experts Science Solutions for Exercise - Embibe Experts Solutions for Chapter: Light - Reflection and Refraction, Exercise 1: Karnataka Board-2019
Attempt the free practice questions on Chapter 10: Light - Reflection and Refraction, Exercise 1: Karnataka Board-2019 with hints and solutions to strengthen your understanding. EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR SCIENCE solutions are prepared by Experienced Embibe Experts.
Questions from Embibe Experts Solutions for Chapter: Light - Reflection and Refraction, Exercise 1: Karnataka Board-2019 with Hints & Solutions