Embibe Experts Solutions for Exercise 4: Assignment

If set $A$ has $3$ elements and set $B$ has $6$ elements then

The set of values of $x$ satisfying $\frac{2x-3}{3x-5}\ge 3$ is

The set of values of '$x$ ' satisfying $\left(x^2-x-1\right) \left(x^2-x-7\right)<-5$is $\left(a,b\right)\cup \left(c,d\right)$ then $a+b+c+d$ is equal to

The solution set for $x{\left(x+2\right)}^2{\left(x-1\right)}^5\left(2x-3\right){\left(x-3\right)}^4\ge 0$ is given by $x\in \left[a,b\right]\cup \left[c,\infty \right)\cup \left\{-2\right\}$ then value of $a+b+c$ is equal to

All real set of values of $x$ satisfying $x^2-3x+2>0$ and $x^2-2x-4\le 0$ are given by $\left[a,b\right)\cup \left(c,d\right]$ then value of $\frac{a+d}{c-b}$ is equal to

If $U=\left\{x:x^5-6x^4+11x^3-6x^2=0\right\}$ $A=\left\{x:x^2-x=0\right\}$ and $B=\left\{x:x^2-2x=0\right\}$ then $n\left(\overline{A\cap B}\right)$ is equal to (where $U$ is universal set and $n\left(A\right)$ denotes number of elements)

Two finite sets have $p$ and $q$ elements. The total number of subsets of the first set is $56$ more than total number of subsets of second set. The value $p·q$ is equal to

Let $A=\left\{a_1,a_2,a_3,a_4\right\}$ where $a_1>a_2>a_3>a_4$. The total number of unordered pairs of disjoint subsets of $A$ is equal to