Embibe Experts Solutions for Exercise 1: EXERCISE 16.1

In a vernier calipers $x$ divisions of main scale division coincide with $x+y$ divisions of vernier scale. For what value of $y$ the instrument has minimum least count?

A screw gauge has main scale divisions of $1 \mathrm{mm}$ each and its circular scale has $100$ divisions while measuring a diameter of a wire, cap end is after ${21}^{\mathrm{st}}$ marking of main scale and ${52}^{\mathrm{nd}}$ division of circular scale coincides with the reference line, what is the measured diameter of the wire

The smallest division on main scale of a vernier calipers is $1 \mathrm{mm}$. Least count of vernier calipers is $0.06 \mathrm{mm}$. While measuring the length of a line, the zero mark of the vernier scale lies between $9.3 \mathrm{cm}$ and $9.4 \mathrm{cm}$ and $5^{\mathrm{th}}$ vernier scale coincide with a main scale division. The length of the wire (in $\mathrm{cm}$) is

The figure shows a situation when jaws of vernier are touching each other one main scale division is of $1 \mathrm{mm}$. The zero correction in reading measured will be

The reading of micrometer screw gauge shown in figure (Least count is $0.01 \mathrm{mm})$

A vernier caliper has $1 \mathrm{mm}$ marks on the main scale. It has $20$ equal divisions on the vernier scale which match with $12$main scale divisions. Its least count is