Embibe Experts Solutions for Exercise 2: EXERCISE 12.2

When the maximum $KE$ of a simple pendulum is $K$, then what is its displacement (in terms of amplitude a), when its $KE$ is $\frac{K}{2} ?$

The kinetic energy of a simple harmonic motion when the particle is half way to its end point is (where $E_0$ is the total energy)

For a particle executing simple harmonic motion, the kinetic energy $K$ is given by, $K=K_0{\cos }^2\omega t.$ The maximum value of potential energy is

Starting from the origin, a body oscillates simple harmonically with a period of $2 \mathrm{s}$. After what time will its kinetic energy be $75\%$ of the total energy?

If a simple pendulum of length $L$ has maximum angular displacement $\alpha$, then the maximum kinetic energy of bob of mass $M$ is

If $U$ is the potential energy of an oscillating particle and $F$ is the force acting on it at a given instant, which of the following is true? (Take $x$ be the displacement of particle from mean position)

A particle starts oscillating in simple harmonic motion from its equilibrium position with time period $T$. The ratio of KE and PE of the particle at time $t=\frac{T}{12}$ is

Starting from the origin, a body oscillates simple harmonically with a period of $2 \mathrm{s}$. After what time will its kinetic energy be $75\%$ of the total energy?