Embibe Experts Solutions for Exercise 1: EXERCISE

In scattering experiment, find the distance of closest approach, if a $6 \mathrm{MeV} \alpha$-particle is used

The angular momentum of an electron in a hydrogen atom is proportional to (where $n$ is principle quantum number)

The energies of three conservative energy levels $L_3, L_2$ and $L_1$ of hydrogen atom are $E_0, \frac{4E_0}{9}$ and $\frac{E_0}{4}$ respectively. A photon of wavelength $\lambda$ is emitted for a transition $L_3$ to $L_1.$ What will be the wavelength of emission for transition $L_2$ to $L_1$ ?

When an electron is excited to $n^{\text{th }}$ excited energy state in hydrogen atom, then the possible number of spectral lines emitted are

In which transition of a hydrogen atom, photons of lowest frequency are emitted?

The binding energy of an electron in $4^{\mathrm{th}}$ orbit of hydrogen atom is

Three energy levels $L_1, L_2$ and $L_3$ of a hydrogen atom correspond to increasing values of energy i.e., $E_{L_1}<E_{L_2}<E_{L_3}.$ If the wavelength corresponding to the transitions $L_3$ to $L_2, L_2$ to $L_1$ and $L_3$ to $L_1$ are ${\lambda }_3, {\lambda }_2$ and ${\lambda }_1$ respectively then

In Bohr's model of the hydrogen atom the ratio between the period of revolution of an electron in the orbit of $\mathrm{n}=1$ to the period of the revolution of the electron in the orbit $\mathrm{n}=2$ is:-