Embibe Experts Solutions for Chapter: Area under Curves, Exercise 1: Level 1

The area of the region bounded by the curve $y^2=4a^2\left(x-1\right)$ and the lines $x=1, y=4a$ is

The area under the curve $y=\left|\cos x-\sin x\right|, 0\le x\le \frac{\pi }{2}$, and above $x-$axis is

The area enclosed between the curves $y=x$ and $y=2x-x^2$ is

The area bounded by the curves $\sqrt{x}+\sqrt{y}=1$ and $x+y=1$, is

If area enclosed by the curves $y=x \ln x$ and $y=2x(1-x)$ is $A$, then $\left[A\right]$ equals, where $\left[*\right]$ denotes greatest integer function.

If $A$ be the area bounded by $x^2+y^2=4$ and $y^2=3x$ and $y$-axis in the first quadrant, then the value of $\frac{10\mathrm{\pi }}{A+{\displaystyle \frac{1}{2\sqrt{3}}}}$ is

The area bounded by the lines $y=\left|\left|x-1\right|-2\right|$ is _____sq. units.

The graphs of sine and cosine functions, intersect each other at a number of points and between two consecutive points of intersection, the two graphs enclose the same area $A$. Then $A^4$ is equal to