Embibe Experts Solutions for Chapter: Current Electricity, Exercise 1: Exercise

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Embibe Experts Physics Solutions for Exercise - Embibe Experts Solutions for Chapter: Current Electricity, Exercise 1: Exercise

Attempt the practice questions on Chapter 6: Current Electricity, Exercise 1: Exercise with hints and solutions to strengthen your understanding. Physics Crash Course (Based on Revised Syllabus-2023) solutions are prepared by Experienced Embibe Experts.

Questions from Embibe Experts Solutions for Chapter: Current Electricity, Exercise 1: Exercise with Hints & Solutions

MEDIUM
12th Andhra Pradesh Board
IMPORTANT

State Joule's law of heating.

MEDIUM
12th Andhra Pradesh Board
IMPORTANT

Derive the expression for power P=V×I, in an electrical circuit.

HARD
12th Andhra Pradesh Board
IMPORTANT

In the Fig., what is the potential difference Vd-Vc between the points d and c if E1=4.0 V, E2=1.0 V, R1=R2=10 Ω, andR3=8.0 Ω and the battery is ideal?

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HARD
12th Andhra Pradesh Board
IMPORTANT

n identical cells, each of emf E and internal resistance r, are connected in series to a resistor R. Deduce an expression for the internal resistance r of one cell in terms of the current I in the circuit.

HARD
12th Andhra Pradesh Board
IMPORTANT

Find the emf of the battery shown in figure.

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HARD
12th Andhra Pradesh Board
IMPORTANT

Find the emf and the internal resistance of an electric source which is equivalent to two batteries of emf's E1 and E2 and internal resistances r1 and r2 connected in parallel.

HARD
12th Andhra Pradesh Board
IMPORTANT

Prove that two identical cells (each of emf E, internal resistance r) will send same current in an external resistance R whether all cells are connected in series or in parallel, if R=r.

HARD
12th Andhra Pradesh Board
IMPORTANT

Two cells, each of emf 1.5 V are joined in series and send 1.0 A current in an external resistor. If the same cells are joined in parallel, then they send 0.6 A current in the same resistor. What is the internal resistance of each cell?