Embibe Experts Solutions for Chapter: Dual Nature of Radiation and Matter, Exercise 1: Exercise

A proton and an electron have same kinetic energy. Which one has greater de Broglie wavelength. Justify.

Write the relationship of de Broglie wavelength $\mathrm{\lambda }$ associated with a particle of mass $\mathrm{m}$ in terms of its kinetic energy $\mathrm{K}$.

An electron and an alpha particle have same kinetic energy. How are the de Broglie wavelengths associated with them related?

What should be the velocity of the electron so that its momentum equals that of $4000 \dot{\mathrm{A}}$ wavelength photon.

Calculate the de Broglie wavelength of a proton whose kinetic energy is equal to $81.9\times {10}^{-15} \mathrm{J}$. (Given: mass of proton is $1836$ times that of electron).

A deuteron and an alpha particle are accelerated with the same potential. Which one of the two has $\left(\mathrm{i}\right)$ greater value of de Broglie wavelength associated with it and $\left(\mathrm{ii}\right)$ less kinetic energy? Explain.

Write down de Broglie's relation and explain the terms therein.

What is the de Broglie wavelength of a ball of mass $0.12 \mathrm{kg}$ moving with a speed of $20 \mathrm{m}/\mathrm{s}$? What can we infer from this result? (Planck's constant $h=6.62\times {10}^{-34} \mathrm{J}·\mathrm{s}$ )