Radius of a nucleus of mass number 16 is 3 × 10 15 m . What is the radius of a nucleus of mass number 128 .

We know that R = R 0 A 1 3 Its given : A 1 = 16 R 1 = 3 × 10 15 m A 2 = 128 Using the above equation: R 2 R 1 = A 2 A 1 1 / 3 = 128 16 1 / 3 = ( 8 ) 1 / 3 = 2 ⇒ R 2 = 2 R 1 = 6 × 10 - 15 m . Here, the symbols have their usual meaning.

What is the number of protons and neutrons in X 32 15 nucleus?

X 32 15 = Z X A For the given nucleus atomic number : Z = 15 Since, atomic number is equal to the number of protons, therefore number of protons = 15 Mass number of nucleus: A = 32 Since mass number is equal to the number of protons + neutron Thus, number of neutrons = A - Z = 32 - 15 = 17

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Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 13 - Nuclei>Exercise

Embibe Experts Solutions for Chapter: Nuclei, Exercise 1: Exercise

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Embibe Experts Physics Solutions for Exercise - Embibe Experts Solutions for Chapter: Nuclei, Exercise 1: Exercise

Attempt the free practice questions on Chapter 13: Nuclei, Exercise 1: Exercise with hints and solutions to strengthen your understanding. Physics Crash Course (Based on Revised Syllabus-2023) solutions are prepared by Experienced Embibe Experts.