Embibe Experts Solutions for Chapter: Oscillations, Exercise 1: Level 1

Find the time period of a particle executing simple harmonic motion in second, if it is known that the potential energy changes from maximum to minimum in $5 \mathrm{s}$.

A body is executing S.H.M. Its potential energy is $E_1$ and $E_2$ at displacements $x$ and $y$ respectively. The potential energy at displacement $\left(x+y\right)$ is

The displacement equations for two waves undergoing superposition are, respectively, $y_1=4\sin \omega t$ and $y_2=3\sin \left(\omega t+\frac{\pi }{2}\right)$. The amplitude of the resultant wave is,

Energy of particle executing $\mathrm{SHM}$ depends upon

The magnitude of average acceleration in half time period from equilibrium position in a simple harmonic motion is,

The coefficient of friction between block of mass $m$ and $2\mathrm{m}$ is $\mu =2\tan \left(\theta \right)$. There is no friction between a block of mass $2\mathrm{m}$ and inclined plane. The maximum amplitude of two block system for which there is no relative motion between both the blocks-

The displacement of a particle is given by, $x={\cos }^2\omega t$. The motion is,

The time period of oscillation of a simple pendulum having length $L$ and mass of the bob $m$ is given as $T$. If the length of the pendulum is increased to $4L$ and the mass of the bob is increased to $2m$, then which one of the following is the new time period of oscillation?