Embibe Experts Solutions for Chapter: Wave Optics, Exercise 1: Exercise#1

In a $\mathrm{YDSE}:$ distance between slits and screen is $D=1 \mathrm{m}\text{, separation between the slits is} \mathrm{d}=1 \mathrm{mm}$ and wavelength of the incident light is $\lambda =5000\mathrm{nm}.$ The distance of ${100}^{\text{th }}$ maxima from the central maxima is:

Let $S_1$ and $S_2$ be the two slits in Young's double slit experiment. If central maxima is observed at $P$ and angle $\angle S_{1}P{S}_2=\mathrm{\theta }$, then the fringe width for the light of wavelength $\lambda$ will be (assume $\theta$ to be a small angle),

The distance of $n^{\mathrm{th}}$ bright fringe to the $(n+1{)}^{\text{th}}$ dark fringe in Young's experiment is equal to,

Two light waves are given by, $E_1=2\sin \left(100\pi t-kx+30°\right)$ and $E_2=3\cos \left(200\pi t-k^{\text{'}}x+60°\right)$
The ratio of intensity of first wave to that of second wave is:

If a torch is used in place of monochromatic light in Young's double-slit experiment, what will happen?

A single slit of width $0.1 \mathrm{mm}$ is illuminated by parallel light of wavelength $6000 \mathrm{A},$ and diffraction bands are observed on a screen $40 \mathrm{cm}$ from the slit. The distance of third dark band from the central bright band is.

A parallel beam of light $\left(\lambda =5000\stackrel{°}{A}\right.)$ is incident at an angle $\alpha =30°$ with the normal to the slit plane in a young's double slit experiment. Assume that the intensity due to each slit at any point on the screen is $I_0.$ Point $O$ is equidistant from $S_1 \& S_2.$ The distance between slits is $1 \mathrm{mm}.$

The meaning of wavefront is:-