G L Mittal and TARUN MITTAL Solutions for Chapter: Motion in Fluids : Viscosity, Exercise 3: FOR DIFFERENT COMPETITIVE EXAMINATIONS
G L Mittal Physics Solutions for Exercise - G L Mittal and TARUN MITTAL Solutions for Chapter: Motion in Fluids : Viscosity, Exercise 3: FOR DIFFERENT COMPETITIVE EXAMINATIONS
Attempt the practice questions on Chapter 17: Motion in Fluids : Viscosity, Exercise 3: FOR DIFFERENT COMPETITIVE EXAMINATIONS with hints and solutions to strengthen your understanding. ISC Physics Class XI Part 1 solutions are prepared by Experienced Embibe Experts.
Questions from G L Mittal and TARUN MITTAL Solutions for Chapter: Motion in Fluids : Viscosity, Exercise 3: FOR DIFFERENT COMPETITIVE EXAMINATIONS with Hints & Solutions
A small lead ball is falling freely in a viscous liquid. The velocity of the ball:

A small spherical solid ball is dropped in a viscous liquid. Its journey in the liquid is best described in the figure by:

If the terminal speed of a sphere of gold ( density) is in a viscous liquid (density). Find the terminal speed of a sphere of silver (density) of the same size in the same liquid:

Spherical balls of radius Are falling in a viscous fluid of viscosity with a velocity . The retarding viscous force acting on the spherical ball is:

The terminal velocity of a small sphere of radius falling through a viscous liquid varies with such that:

A spherical solid ball of volume is made of a material of density . It is falling through a liquid of density . Assume that the liquid applies a viscous force on the ball that is proportional to the square of its speed that is . The terminal speed of the ball is:

The terminal velocity of a small steel ball of mass and radius falling under gravity through air (viscosity ) depends upon , , and . Which of the following relations must be dimensionally correct?

The velocity of a small ball of mass and density , when dropped in a container filled with glycerine becomes constant after some time. If the density of glycerine is , the viscous force acting on the ball will be:
