Embibe Experts Solutions for Chapter: Current Electricity, Exercise 1: Exercise 1

The reading of a high resistance voltmeter, when a cell is connected across it is $2.2 \mathrm{V}$. When the terminals of the cell are also connected to a resistance of $5 \mathrm{\Omega }$  as shown in the circuit, the voltmeter reading drops to $1.8 \mathrm{V}$. The internal resistance of the cell is:

In the circuit shown in the figure

Capacitor $C_1$ is charged to a potential of $V.$ The current in the circuit just after the switch $S$ is closed

Under steady state condition

In the circuit shown, the switch is shifted from position $1\to 2$ at $t=0.$ The switch was initially in position $1$ since long time. The graph between charge on capacitor $C$ and time$\text{'}f\text{'}$ is

For the given arrangement shown in figure. The switch is closed at $t=0$ The time after which the current becomes $2.5\mathrm{\mu A}$ is

A capacitor charges from a cell through a resistance the time constant is $T.$ In what time will the capacitor collect $10\%$ of its final charge?

The charge on a capacitor decreases to $n$ times of its initial value in time $t,$ when it discharges through a circuit with a time constant $T.$ The relation between $t$ and $T$ would be:

In the given circuit at $t=0, S$ is closed, then at time $t, \frac{i_1}{i_2}$