H C Verma Solutions for Chapter: X-rays, Exercise 2: OBJECTIVE
H C Verma Physics Solutions for Exercise - H C Verma Solutions for Chapter: X-rays, Exercise 2: OBJECTIVE
Attempt the practice questions on Chapter 22: X-rays, Exercise 2: OBJECTIVE with hints and solutions to strengthen your understanding. CONCEPTS OF PHYSICS [VOLUME 2] solutions are prepared by Experienced Embibe Experts.
Questions from H C Verma Solutions for Chapter: X-rays, Exercise 2: OBJECTIVE with Hints & Solutions
Frequencies of X-rays of different materials are measured. Which one of the graphs in the figure may represent the relation between the frequency and the atomic number .

The X-ray beam coming from an X-ray tube

One of the following wavelengths is absent and the rest are present in the X-rays coming from a Coolidge tube. Which one is the absent wavelength?

The figure shows the intensity-wavelength relations of rays coming from two different Coolidge tubes. The solid curve represents the relation for the tube in which the potential difference between the target and the filament is and the atomic number of the target material is . These quantities are and for the other tube. Then,

of the X-ray coming from a Coolidge tube is able to pass through a thick aluminium foil. If the potential difference between the target and the filament is increased, the fraction of the X-ray passing through the same foil will be

of the X-ray coming from a Coolidge tube is able to pass through a thick aluminium foil. The potential difference between the target and the filament is increased. The thickness of aluminum foil, which will allow of the X-ray to pass through, will be

ray from a Coolidge tube is incident on a thin aluminium foil. The intensity of the ray transmitted by the foil is found to be . The heating current is increased so as to increase the temperature of the filament. The intensity of the ray transmitted by the foil will be

Visible light passing through a circular hole forms a diffraction disc of radius on a screen. If X-ray is passed through the same set-up, the radius of the diffraction disc will be
