J P Mohindru and Bharat Mohindru Solutions for Chapter: Arithmetic Progressions, Exercise 10: CHAPTER TEST

Which term of the A.P.: $3$, $15$, $27$, $39$, ... will be $132$ more than its ${54}^{\mathrm{th}}$ term?

How many multiples of $4$ lie between $10$ and $250$? 

Find the sum of the following A.P.: $\frac{1}{15}$, $\frac{1}{12}$, $\frac{1}{10}$,... to $11$ terms

How many terms of the A.P. $9$, $17$, $25$, ... must be taken to give a sum of $636$?  

Find the sum of first $51$ terms of an A.P. whose second and third terms are $14$ and $18$ respectively.

If $m$ times the $m^{\mathrm{th}}$ term of an A.P. is equal to $n$ times its $n^{\mathrm{th}}$ term, show that the ${\left(m+n\right)}^{\mathrm{th}}$ th term of the A.P is zero.

 Determine the A.P. whose fifth term is $19$ and the difference of the eighth terms from the thirteenth term is $20$. 

Find the sum: $\frac{a-b}{a+b}+\frac{3a-2b}{a+b}+\frac{5a-3b}{a+b}+$....$+11$ terms.