J P Mohindru and Bharat Mohindru Solutions for Chapter: Quadratic Equations, Exercise 7: EXERCISE

Author:J P Mohindru & Bharat Mohindru

J P Mohindru Mathematics Solutions for Exercise - J P Mohindru and Bharat Mohindru Solutions for Chapter: Quadratic Equations, Exercise 7: EXERCISE

Attempt the free practice questions on Chapter 4: Quadratic Equations, Exercise 7: EXERCISE with hints and solutions to strengthen your understanding. Modern's abc+ of Mathematics for Class 10 solutions are prepared by Experienced Embibe Experts.

Questions from J P Mohindru and Bharat Mohindru Solutions for Chapter: Quadratic Equations, Exercise 7: EXERCISE with Hints & Solutions

MEDIUM
10th CBSE
IMPORTANT

The difference of two numbers is 5 and the difference of their reciprocals is 110. Find the numbers.

MEDIUM
10th CBSE
IMPORTANT

Three consecutive positive integers are such that the sum of the square of the first and the product of other two is 46, find the integers.

MEDIUM
10th CBSE
IMPORTANT

The difference of squares of two natural numbers is 45. The square of the smaller number is 8 times the larger number. Find the two numbers.

Note: The question given in the textbook seems to be wrong. The correct question should be as below:

The difference of squares of two natural numbers is 45. The square of the smaller number is 4 times the larger number. Find the two numbers.

MEDIUM
10th CBSE
IMPORTANT

A two-digit number is such that the product of the digits is 15. If 18 is added to the number, the digits are interchanged. Find the number.

MEDIUM
10th CBSE
IMPORTANT

Divide 16 two parts such that twice the square of the larger part exceeds the square of the smaller part by 164

MEDIUM
10th CBSE
IMPORTANT

A two-digit number is such that product of its digits is 14. If 45 is added to the number, the digits interchange the places. Find the number.

MEDIUM
10th CBSE
IMPORTANT

The denominator of a fraction is 3 more than its numerator. The sum of the fraction and its reciprocal is 2910. Find the fraction.

MEDIUM
10th CBSE
IMPORTANT

The sum of first n even natural number is given by the relation S=n (n+1). Find n if the sum is 420.