J P Mohindru and Bharat Mohindru Solutions for Chapter: Quadratic Equations, Exercise 8: EXERCISE

One year ago, a man was $8$ times as old as his son. Now his age is equal to the square of his son's age find their present age.

The sum of the age of a man his son is $45$ years. Five years ago, the product of their ages was four times the man's age at that time. Find their present ages.

A girl is twice as old her sister. Four years hence, the product of their ages (in years) will be $160$. Find their present ages.

The difference of a father's age and his son's age is $21$ years and twelfth part of the product of their ages is less the father's age by $18$ years. Find their ages.

Arun is $k$ years old while his mother's Mrs. Khanna is $k^2$ years old. $5$ years hence, Mrs. Khanna will be three times as old as Arun. Find their present ages.

The sum of the ages of a boy and his brother is $25$ years, and the product of their ages in years is $126$. Find their ages.

The product of Reena's age (in years) $5$ years ago and her age $8$ years later is $30$. Find her present age.