J P Mohindru and Bharat Mohindru Solutions for Chapter: Quadratic Equations, Exercise 8: EXERCISE
J P Mohindru Mathematics Solutions for Exercise - J P Mohindru and Bharat Mohindru Solutions for Chapter: Quadratic Equations, Exercise 8: EXERCISE
Attempt the free practice questions on Chapter 4: Quadratic Equations, Exercise 8: EXERCISE with hints and solutions to strengthen your understanding. Modern's abc+ of Mathematics for Class 10 solutions are prepared by Experienced Embibe Experts.
Questions from J P Mohindru and Bharat Mohindru Solutions for Chapter: Quadratic Equations, Exercise 8: EXERCISE with Hints & Solutions
One year ago, a man was times as old as his son. Now his age is equal to the square of his son's age find their present age.

The sum of the age of a man his son is years. Five years ago, the product of their ages was four times the man's age at that time. Find their present ages.

A girl is twice as old her sister. Four years hence, the product of their ages (in years) will be . Find their present ages.

The difference of a father's age and his son's age is years and twelfth part of the product of their ages is less the father's age by years. Find their ages.

Arun is years old while his mother's Mrs. Khanna is years old. years hence, Mrs. Khanna will be three times as old as Arun. Find their present ages.

The sum of the ages of a boy and his brother is years, and the product of their ages in years is . Find their ages.

The product of Reena's age (in years) years ago and her age years later is . Find her present age.
