J P Mohindru and Bharat Mohindru Solutions for Chapter: Quadratic Equations, Exercise 8: EXERCISE

Author:J P Mohindru & Bharat Mohindru

J P Mohindru Mathematics Solutions for Exercise - J P Mohindru and Bharat Mohindru Solutions for Chapter: Quadratic Equations, Exercise 8: EXERCISE

Attempt the free practice questions on Chapter 4: Quadratic Equations, Exercise 8: EXERCISE with hints and solutions to strengthen your understanding. Modern's abc+ of Mathematics for Class 10 solutions are prepared by Experienced Embibe Experts.

Questions from J P Mohindru and Bharat Mohindru Solutions for Chapter: Quadratic Equations, Exercise 8: EXERCISE with Hints & Solutions

MEDIUM
10th CBSE
IMPORTANT

One year ago, a man was 8 times as old as his son. Now his age is equal to the square of his son's age find their present age.

MEDIUM
10th CBSE
IMPORTANT

The sum of the age of a man his son is 45 years. Five years ago, the product of their ages was four times the man's age at that time. Find their present ages.

MEDIUM
10th CBSE
IMPORTANT

A girl is twice as old her sister. Four years hence, the product of their ages (in years) will be 160. Find their present ages.

MEDIUM
10th CBSE
IMPORTANT

The difference of a father's age and his son's age is 21 years and twelfth part of the product of their ages is less the father's age by 18 years. Find their ages.

MEDIUM
10th CBSE
IMPORTANT

Arun is k years old while his mother's Mrs. Khanna is k2 years old. 5 years hence, Mrs. Khanna will be three times as old as Arun. Find their present ages.

MEDIUM
10th CBSE
IMPORTANT

The sum of the ages of a boy and his brother is 25 years, and the product of their ages in years is 126. Find their ages.

MEDIUM
10th CBSE
IMPORTANT

The product of Reena's age (in years) 5 years ago and her age 8 years later is 30. Find her present age.