We have to find the value of 24 ÷ 25 . We use the long division method. If the remainder is less than the dividend, then insert a decimal point in the quotient to add extra zero. If the last remainder is non-zero, insert as many zeros on the right of decimal part of the dividend as needed to make the last remainder zero. 0 . 96 25 24 - 0 240 - 225 150 - 150 0 Therefore, the required value is 24 ÷ 25 = 0 . 96 .

We have to find the value of 135 ÷ 2 . We use the long division method. If the remainder is less than the dividend, then insert a decimal point in the quotient to add extra zero. If the last remainder is non-zero, insert as many zeros on the right of decimal part of the dividend as needed to make the last remainder zero. 67 . 5 2 135 - 12 15 - 14 10 - 10 0 Therefore, the required value is 135 ÷ 2 = 67 . 5 .

We have to find the value of 796 ÷ 3184 . We use the long division method. If the remainder is less than the dividend, then insert a decimal point in the quotient to add extra zero. If the last remainder is non-zero, insert as many zeros on the right of decimal part of the dividend as needed to make the last remainder zero. 0 . 25 3184 796 - 0 7960 - 6368 15920 - 15920 0 Therefore, the required value is 796 ÷ 3184 = 0 . 25 .

We have to find the value of 6 ÷ 125 . We use the long division method. If the remainder is less than the dividend, then insert a decimal point in the quotient to add extra zero. If the last remainder is non-zero, insert as many zeros on the right of decimal part of the dividend as needed to make the last remainder zero. 0 . 048 125 6 - 0 60 - 0 600 - 500 1000 - 1000 0 Therefore, the required value is 6 ÷ 125 = 0 . 048 .

We have to find the value of 17 ÷ 40 . We use the long division method. If the remainder is less than the dividend, then insert a decimal point in the quotient to add extra zero. If the last remainder is non-zero, insert as many zeros on the right of decimal part of the dividend as needed to make the last remainder zero. 0 . 425 40 17 - 0 170 - 160 100 - 80 200 - 200 0 Therefore, the required value is 17 ÷ 40 = 0 . 425 .

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Step by Step Mathematics>Chapter 3 - Decimals>EXERCISE 3.3

Jagat Jitendra Matto Solutions for Chapter: Decimals, Exercise 3: EXERCISE 3.3

Author:Jagat Jitendra Matto

Jagat Jitendra Matto Mathematics Solutions for Exercise - Jagat Jitendra Matto Solutions for Chapter: Decimals, Exercise 3: EXERCISE 3.3

Attempt the free practice questions on Chapter 3: Decimals, Exercise 3: EXERCISE 3.3 with hints and solutions to strengthen your understanding. Step by Step Mathematics solutions are prepared by Experienced Embibe Experts.