Given fraction is 3 4 of a year. We see that 'of' represents multiplication. We know that, 1 year = 12 months. 3 4 of a year = 3 4 of 12 months = 3 4 × 12 months = 3 × 12 4 months = 36 4 months ⇒ 3 4 of a year = 9 months Therefore, the required value is 9 months.

Given fraction is 2 5 of a rupee. We see that 'of' represents multiplication. We know that, 1 rupee = 100 paise. 2 5 of a rupee = 2 5 of 100 paise = 2 5 × 100 paise = 2 × 100 5 paise = 200 5 paise ⇒ 2 5 of a rupee = 40 paise Therefore, the required value is 40 paise.

Given fraction is 1 4 of an hour. We see that 'of' represents multiplication. We know that, 1 hour = 60 minutes. 1 4 of an hour = 1 4 of 60 minutes = 1 4 × 60 minutes = 1 × 60 4 minutes = 60 4 minutes ⇒ 1 4 of an hour = 15 minutes Therefore, the required value is 15 minutes.

Find 11 25 of a litre.

Given fraction is 11 25 of a litre. We see that 'of' represents multiplication. We know that, 1 litre = 1000 ml. 11 25 of a litre = 11 25 of 1000 ml = 11 25 × 1000 ml = 11 × 1000 25 ml = 11000 25 ml ⇒ 11 25 of a litre = 440 ml Therefore, the required value is 440 ml.

A rectangular park is 21 3 7 m long and 12 3 5 m wide. What is the area of the park?

Given, the length of a rectangular park as 21 3 7 m. The width of a rectangular park is 12 3 5 m. The area of a rectangular park is = length × width . = 21 3 7 × 12 3 5 = 21 × 7 + 3 7 × 12 × 5 + 3 5 = 147 + 3 7 × 60 + 3 5 = 150 7 × 63 5 = 150 × 63 7 × 5 = 30 × 9 = 270 sq . m Therefore, the area of the park is 270 sq . m .

Apples are sold at ₹ 15 3 4 per kg . Find the cost of 6 1 2 kg of apples.

Given, the cost of 1 kg of apples = ₹ 15 3 4 = ₹ 15 × 4 + 3 4 = ₹ 60 + 3 4 = ₹ 63 4 . We have to find the cost of 6 1 2 kg of apples. The cost of 6 1 2 kg of apples = 6 1 2 × ₹ 63 4 = ₹ 6 × 2 + 1 2 × 63 4 = ₹ 13 2 × 63 4 = ₹ 13 × 63 2 × 4 = ₹ 819 8 = ₹ 102 3 8 . Therefore, the cost of 6 1 2 kg of apples is ₹ 102 3 8 .

Rohit covers 2 2 5 km in one hour. How much distance will he cover in 3 1 3 hours?

Given, the distance Rohit covers in 1 hour = 2 2 5 km = 2 × 5 + 2 5 km = 12 5 km . We have to find the distance that he will cover in 3 1 3 = 3 × 3 + 1 3 = 10 3 hours. The distance Rohit covers in 10 3 hours = 10 3 × 12 5 km = 10 3 × 12 5 km = 10 × 12 3 × 5 km = 120 15 km = 8 km Therefore, the distance covered in 3 1 3 hours is 8 km .

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Step by Step Mathematics>Chapter 2 - Fractions>EXERCISE 2.3

Jagat Jitendra Matto Solutions for Chapter: Fractions, Exercise 4: EXERCISE 2.3

Author:Jagat Jitendra Matto

Jagat Jitendra Matto Mathematics Solutions for Exercise - Jagat Jitendra Matto Solutions for Chapter: Fractions, Exercise 4: EXERCISE 2.3

Attempt the free practice questions on Chapter 2: Fractions, Exercise 4: EXERCISE 2.3 with hints and solutions to strengthen your understanding. Step by Step Mathematics solutions are prepared by Experienced Embibe Experts.