Jagat Jitendra Matto Solutions for Chapter: Perimeter and Area, Exercise 7: EXERCISE 13.6

Author:Jagat Jitendra Matto

Jagat Jitendra Matto Mathematics Solutions for Exercise - Jagat Jitendra Matto Solutions for Chapter: Perimeter and Area, Exercise 7: EXERCISE 13.6

Attempt the free practice questions on Chapter 13: Perimeter and Area, Exercise 7: EXERCISE 13.6 with hints and solutions to strengthen your understanding. Step by Step Mathematics solutions are prepared by Experienced Embibe Experts.

Questions from Jagat Jitendra Matto Solutions for Chapter: Perimeter and Area, Exercise 7: EXERCISE 13.6 with Hints & Solutions

EASY
7th CBSE
IMPORTANT

The radius of one circular field is 5 m and that of other is 3 m. The radius of the circular field is x m whose area is the difference of the areas of the first and second field. Find the value of x.

EASY
7th CBSE
IMPORTANT

A square park has its side 32 m. At each corner of the park, there is a flower bed in the form of a quadrant of radius 10 m as shown in the figure. The area of the remaining part of the park is x m2. Find the value of x.(Take π=3.14)

Question Image

EASY
7th CBSE
IMPORTANT

The area of two circles are in the ratio 9:16. Find the ratio of their circumferences.

EASY
7th CBSE
IMPORTANT

The ratio of radii of two circles is 3:5. Find the ratio of their circumferences.

EASY
7th CBSE
IMPORTANT

The ratio of radii of two circles is 3:5. Find the ratio of their areas

EASY
7th CBSE
IMPORTANT

The inner circumference of a circular track is 264 m and the width of the track is 7 m. Calculate the cost of putting up a fence along the outer circle of the track at the rate of 3.50 per metre. (in )

EASY
7th CBSE
IMPORTANT

The inner circumference of a circular track is 264 m and the width of the track is 7 m. The area of the track is x m2. Find the value of x.

EASY
7th CBSE
IMPORTANT

A circle of radius 5 cm is cut out from a square piece of an aluminium sheet of side 10 cm. What is The area of the remaining aluminium sheet is x cm2. Find the value of x? (Take π=3.14)