MISCELLANEOUS EXERCISE

The diameter of a sphere is $2.25\times {10}^6 \mathrm{metres}$ and diameter of another sphere is $1.5\times {10}^4 \mathrm{metres}$. Find the ratio of the two diameters. How many times the diameter of the first is greater than the diameter of second sphere?

Add: $2.203\times {10}^{27}+3.312\times {10}^{24}$

Subtract: $1.002\times {10}^9-2.34\times {10}^7$

Simplify: $\frac{7\times {10}^{-4}+6\times {10}^{-5}+\left(2.6\right)\times {10}^{-5}}{{10}^{-3}+2\times {10}^{-4}+\left(1.1\right)\times {10}^{-4}}$

By the laws of exponents, if $a^m÷a^n=$ $a^k$, then $k=$_____

If ${\left(a^m\right)}^n=$$a^k$, then $k=$_____

${\left\{{\left(\frac{2}{3}\right)}^{-1}+\frac{3}{2}\right\}}^0+{\left(-1\right)}^2=$ _____

$1^0+2^1+3^2=$