Jitender Gupta and Divya Malik Solutions for Exercise 4: CHALLENGERS

Find the range of values of $x$ which satisfy the inequation, $(x+1{)}^2-(x-1{)}^2<6$.

The maximum value of $23-\left|2x+3\right|$ is

The solution set of the inequation $\frac{1}{5+3x}\le 0$ is 

Solve the inequation $\frac{2}{\left|x-4\right|}>1, x\ne 4$

Solve for $x$ :$\left|x+1\right|+\left|x\right|>3$

Graph the range of the inequation $-2\frac{2}{3}\le x+\frac{1}{3}\le 3\frac{1}{3},\forall x\in R$ on the number line. If the solution set is considered as a diagonal of a square on the number line, then the area of the obtained figure, is

Graph the solution set of $-2<2x-6$ or $-2x+5\ge 13$ where $x\in R$. If we shift the origin at the position $1$, then the new solution set, is

The solution sets $P$ and $Q$ on the number line are given below.

Consider the number line $P$ on $Y-$axis and the number line $Q$ on $X-$axis. Then, find the number of all the pairs of coordinates of the solution set.