K K Sharma Solutions for Chapter: Electromagnetic Induction, Exercise 15: LR Circuit

Author:K K Sharma

K K Sharma Physics Solutions for Exercise - K K Sharma Solutions for Chapter: Electromagnetic Induction, Exercise 15: LR Circuit

Attempt the practice questions on Chapter 3: Electromagnetic Induction, Exercise 15: LR Circuit with hints and solutions to strengthen your understanding. Chapterwise/Topicwise Daily Practice Problems (DPP) Magnetism and Electromagnetic Induction NEET solutions are prepared by Experienced Embibe Experts.

Questions from K K Sharma Solutions for Chapter: Electromagnetic Induction, Exercise 15: LR Circuit with Hints & Solutions

EASY
NEET
IMPORTANT

An inductor L=100 mH, a resistor R=100 Ω and a battery E=100 V are initially connected in series, as shown in the figure. After a long time, the battery is disconnected after short circuiting the points A and B. The current in the circuit, 1 ms after the short circuit, is 

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EASY
NEET
IMPORTANT

For the given circuit, calculate the current which is given by the battery:    

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(i)  just after closing the key.

(ii) long time after closing the key.

HARD
NEET
IMPORTANT

A coil of inductance 300 mH and resistance 2 Ω is connected to a source of voltage 2 V. The current reaches half of its steady-state value in,

HARD
NEET
IMPORTANT

In the given circuit, find the ratio of i1 to i2, where i1 is the initial current and i2 is the steady-state current through the battery.

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EASY
NEET
IMPORTANT

The ratio of time constant in charging and discharging in the circuit shown in the figure is 

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HARD
NEET
IMPORTANT

The time constant of an inductance coil is 2.0×10-3 s. When a 90 Ω resistance is joined in series, the time constant becomes 0.5×10-3 s. The inductance and resistance of the coil, respectively, are,

HARD
NEET
IMPORTANT

The network shown in the figure is a part of a complete circuit. If at a certain instant, the current I is 5 A and is decreasing at the rate of 103 A/s, then VB -VA = ____ V.

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