K K Sharma Solutions for Chapter: Work, Energy and Power, Exercise 1: TOPICWISE QUESTIONS

From an automatic gun, a man fires $360$ bullets per minute with a speed of $360 \mathrm{km} {\mathrm{h}}^{-1}$. If each bullet weighs $20 \mathrm{g}$, the power of the gun is

Power of a water pump is $2 \mathrm{kW}$. If $g=10 \mathrm{m} {\mathrm{s}}^{-2}$, then the amount of water that can raise in $1 \mathrm{minute}$ to a height of $10 \mathrm{m}$ is

Two bodies of masses $m_1$ and $m_2$ $\left(m_2>m_1\right)$ are connected by a light inextensible string which passes through a smooth fixed pulley. The instantaneous power delivered by an external agent to pull $m_1$ with constant velocity $v$ is

A force $\overrightarrow{F}=(3\hat{\mathrm{i}}+4\hat{\mathrm{j}}) \mathrm{N}$ acts on a $2 \mathrm{kg}$ movable object that moves from an initial position $\overrightarrow{d_{\mathrm{i}}}=(-3\hat{\mathrm{i}}-2\hat{\mathrm{j}}) \mathrm{m}$ to a final position $\overrightarrow{d_{\mathrm{f}}}=(5\hat{\mathrm{i}}+4\hat{\mathrm{j}}) \mathrm{m}$ in $6 \mathrm{s}$. The average power delivered by the force during the interval is equal to

A block of mass $m$ slides along the horizontal track with kinetic friction $\mu$. A man pulls the block through a light rope which makes an angle $\text{θ}$ with the horizontal, as shown in the figure. The tension in the light rope is $T$, as shown. The block moves with constant speed $V$. Power delivered by the man to the block is

A power $\left(P\right)$ versus position $\left(x\right)$ graph for a particle is shown below. The particle is of mass $\frac{10}{7} \mathrm{kg}$ and is moving in a positive $x$-direction. Its initial position is $x=0$ and the initial velocity is $1 \mathrm{m} {\mathrm{s}}^{-1}$. The velocity at $x=10$ is 

Power supplied to a particle of mass $2 \mathrm{kg}$ varies with time as $P=\frac{3t^2}{2} \mathrm{watt}$. Here, $t$ is time in $\mathrm{second}$. If the velocity of the particle at $t=0 \mathrm{s}$ is $v=0 \mathrm{m} {\mathrm{s}}^{-1}$, then the velocity of a particle at a time $t=2 \mathrm{s}$ will be

A particle of mass $2 \mathrm{kg}$ starts to move at position $x=0 \mathrm{m}$ and time $t=0 \mathrm{s}$, under the action of force $F=\left(10+4x\right) \mathrm{N}$ along the $x$-axis, on a frictionless horizontal track. If the power delivered by the force (in $\mathrm{watt}$) at the instant the particle has moved by the distance $5 \mathrm{m}$ is $y\times {10}^2 \mathrm{W}$, then find the value of $y$.